Again, I assume this is ppm w/v.
Volume of 25 kg seawater is
v = m/d = 5000 g/1.025 g/mL = 4878 mL. Then mg Pb/L = ? mg/L = ppm w/v
What is the concentration of Pb in mg/L , if you have 25 mg Pb in 5kg of seawater? (note: density of seawater is 1.025 kg/L)
2 answers
Thank you!