The whole idea here is that you have an equation that tells you what is going on AND you have measured quantities of each; therefore, you can calculate the missing quantity of the other one.
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
How many moles acid did we use? That is M x L = ?
Now use the coefficients in the balanced equation to convert mols H2SO4 to mols NaOH. mols NaOH = 2 x mols H2SO4
Now what is the molarity of the NaOH?
M = mole/L (that's the definition of molarity)
MNaOH = mols NaOH/L NaOH.
You know mols NaOH and L NaOH, solve for M NaOH.
What is the concentration of NaOH?
using this solution (0.04756 M (i think its stand for Molarity) H2SO4) what is the concentration of NaOH in 10.00 ml of a solution, titrate to an end point using 24.22 ml of acid?
formula that was given is (H2SO4 + 2NaOH --> Na2SO4 (aq) + 2H20 (l)
please explain how you got the answer, i just don't understand
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