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What is the concentration of a solution of HCL in which a 10.0 mL sample of acid required 50.0 mL of 0.150 M NaOH for neutralization?

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HCL stands for "a" and NaOH stands for "b"
0.050Lb*0.150molb/1Lb*0.010La/1molb*1mola/1La = o.oo33moles of the acid (HCL)

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