What is the concentration of a solution made by diluting 95 mL of 6.0 M HCl to a final volume of 750 mL

Answer 1

c1v1 = c2v2
6.0*95 = c*750
c = ?

Answer 2

A 0.105-L sample of an unknown HNO3 solution required 36.9 mL of 0.200 M Ba(OH)2 for complete neutralization. What was the concentration of the HNO3 solution?

Answer 3

I just did this on my Homework
C1V1=C2V2
6.0*95=C2*750
6*95=570
570=C2*750
Balance the equation using algrebra
570/750=750/750
0.76/1= 0.76
0.76 M