The final volume of the solution after diluting is 410 mL.
Using the formula for dilution:
M1V1 = M2V2
(4.7 M)(13.0 mL) = M2(410 mL)
M2 = (4.7 M)(13.0 mL) / 410 mL
M2 = 0.149 M
Therefore, the concentration of the final solution is 0.149 M.
What is the concentration of a solution formed by diluting 13.0 mL of a 4.7 M glucose solution to 410. mL? Be sure your answer has the correct number
significant figures.
M
10
1 answer