m1v1=m2v2
m1=m2v2/v1
m1=(0.20M NaCl)(.0036)/(0.01)
m1=7.2x10^-4(0.01)
m1=7.2x10^-6
What is the concentration of a HNO3 solution if 10.0 mL of the solution is neutralized by 3.6 mL of a 0.20 M NaOH solution?
4 answers
kkn
march 10
m1=m2v2/v1
m1=(0.20M NaCl)*(.0036)/(0.01)
m1=7.2x10^-4/(0.01)
m1=0.072
m1=(0.20M NaCl)*(.0036)/(0.01)
m1=7.2x10^-4/(0.01)
m1=0.072