Huh. where's your work? What do you even mean? Here's one way. The center lies at the intersection of the perpendicular bisectors of two chords.
KL has slope -7 and midpoint (11/2,3/2)
KM has slope 3 and midpoint (7/2,1/2)
So now the center lies at the intersection of
y - 3/2 = 1/7 (x - 11/2)
y - 1/2 = -1/3 (x - 7/2)
The center is at C=(2,1)
The radius CK is 5
So the equation is (x-2)^2 + (y-1)^2 = 25
Or, you can brute-force it out by solving
(5-h)^2 + (5-k)^2 = r^2
(6-h)^2 + (-2-k)^2 = r^2
(r-h)^2 + (-4-k)^2 = r^2
which method did you try?
What is the center and radius of
K(5,5) L(6,-2) M(2,-4)
I try it but it's not equal to each other. Please help me
1 answer
1 answer