In the given reaction:
\[ NH_2^- + CH_3OH \rightarrow NH_3 + CH_3O^- \]
A Brønsted-Lowry base is defined as a substance that accepts a proton (H⁺).
In this reaction, the species that acts as a Brønsted-Lowry base is the NH2− (amide ion) because it accepts a proton from CH3OH (methanol), resulting in the formation of NH3 (ammonia).
Therefore, the correct answer is:
NH2− (cap n cap h sub 2 raised to the negative power).