In the reaction:
\[ \text{NH}_2^- + \text{CH}_3\text{OH} \rightarrow \text{NH}_3 + \text{CH}_3\text{O}^- \]
the Brønsted-Lowry base is the species that accepts a proton (H⁺). In this case, the \(\text{NH}_2^-\) (amide ion) accepts a proton from \(\text{CH}_3\text{OH}\) (methanol) to form \(\text{NH}_3\) (ammonia).
Therefore, the Brønsted-Lowry base in this reaction is:
NH2− (amide ion).