that is just the slope of the secant line over the interval:
(f(5)-f(0))/(5-0)
What is the average rate of change for the function f(x) = x^3 − 6x^2 + 4x +7 over the interval 0≤x≤5?
5 answers
what's the rate of change though?
it is the value of the expression I gave you. Surely by now you can plug in a value for x and calculate f(x) ? So, the average ate of change over the interval is
(5^3 − 6*5^2 + 4*5x +7)-(0^3 − 6*0^2 + 4*0 +7))/(5-0)
Looks like you need to review this section.
(5^3 − 6*5^2 + 4*5x +7)-(0^3 − 6*0^2 + 4*0 +7))/(5-0)
Looks like you need to review this section.
bruh i came here to cheat gimmi the answer
the people on here that decide to give you another even longer equation than the answer are straight virgins : | no playin
1 answer