We can use the formula for the area of a triangle, which is A = (1/2)bh, where b is the base and h is the height.
First, we need to find the length of QR. Using the Pythagorean theorem, we can find that QR = √(8^2 + 14^2) = 16.2 m (rounded to the nearest tenth).
Next, we need to find the height of the triangle. We can draw a perpendicular line from P to QR and label the intersection point as S. Then we can use the Pythagorean theorem again to find that PS = √(10^2 + 8^2) = 12.8 m (rounded to the nearest tenth).
Finally, we can use the formula for the area of a triangle:
A = (1/2)bh = (1/2)(16.2)(12.8) ≈ 104.0 m^2
Rounding to the nearest tenth, we get A ≈ 104.0 ≈ 104.1 m^2, which means the answer is (a) 24.1 m^2.
What is the area of triangle ΔPQR to the nearest tenth of a square meter. Drawing is not to scale.
Image: www(dot)connexus(dot)com/content/media/796450-6262013-91212-AM-1110835710(dot)jpg
a. 24.1 m^2
b. 34.4 m^2
c. 48.2 m^2
d. 68.8 m^2
1 answer
1 answer