The formula for the area of a sector is:
A = (θ/360)πr^2
where θ is the central angle in degrees, r is the radius, and π is pi.
Plugging in the given values, we get:
A = (60/360)π(2)^2
A = (1/6)π(4)
A = 2/3π
Rounding to the nearest tenth, we get:
A ≈ 2.1
Therefore, the area of the sector is 2/3π or 2.1 square meters (rounded).
What is the area of the sector with a central angle of 60° and a radius 2m? Round your answer to the nearest tenth or leave in terms of π.
Your answer should be:
⅔π
Show work.
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1 answer