The formula for the area of a sector is:
A = (θ/360)πr^2
where θ is the central angle in degrees, r is the radius, and π is approximately 3.14.
Plugging in the given values, we get:
A = (60/360)π(2^2)
A = (1/6)π(4)
A ≈ 2.1
Rounding to the nearest tenth, the area of the sector is 2.1 square meters.
What is the area of the sector with a central angle of 60° and a radius 2m? Round your answer to the nearest tenth or leave in terms of π.
Show work.
1 answer