What is the area of the sector of a circle with θ=115° and a radius of 6 cm? Include pi in your calculation.(1 point)

Responses

A=36.13 cm2
upper A equals 36.13 cm squared

A=76.97 cm2
upper A equals 76.97 cm squared

A=113.10 cm2
upper A equals 113.10 cm squared

A=6.02 cm2
upper A equals 6.02 cm squared
Rema

1 answer

To find the area of a sector of a circle, you can use the formula:

\[ A = \frac{\theta}{360^\circ} \times \pi r^2 \]

where:

  • \(A\) is the area of the sector,
  • \(\theta\) is the angle in degrees,
  • \(r\) is the radius of the circle.

Given:

  • \(\theta = 115^\circ\)
  • \(r = 6 , \text{cm}\)

Now we can substitute the values into the formula:

\[ A = \frac{115}{360} \times \pi \times (6)^2 \]

First, calculate \( (6)^2 \):

\[ (6)^2 = 36 \]

Now substitute this into the formula:

\[ A = \frac{115}{360} \times \pi \times 36 \]

Next, calculate \( \frac{115 \times 36}{360} \):

\[ \frac{115 \times 36}{360} = \frac{4140}{360} = 11.5 \]

Now substitute back into the area formula:

\[ A = 11.5 \pi \]

Using an approximate value for \(\pi \approx 3.14\) to find the numerical area:

\[ A \approx 11.5 \times 3.14 \approx 36.13 , \text{cm}^2 \]

Thus, the area of the sector is:

\[ \boxed{36.13 , \text{cm}^2} \]