To find the area of the parallelogram shown, we use the formula Area = base x height. Since the base is 12 inches and the height is 5 inches, the area is 12 x 5 = 60 square inches. So the correct answer to the first question is A) 60 in^2.
For the second question, if the base is 5 inches longer (17 inches) and the height is 5 inches taller (10 inches), the new area would be 17 x 10 = 170 square inches. So the correct answer is not listed, the closest would be A) 230 in^2.
What is the area of the parallelogram shown?
Responses
A 60
60 in 2
B 120
120 in 2
C 140
140 in 2
D 180
180 in 2
Question 2
What is the area of a parallelogram that has a base 5 inches longer and a height 5 inches taller than the parallelogram shown?
Responses
A 230
230 in 2
B 260
260 in 2
C 290
290 in 2
D 310
3 answers
Find the area of this isosceles trapezoid.
Responses
A 38.75
38.75 in 2
B 77.5
77.5 in 2
C 155
155 in 2
D 198
198 in 2
Responses
A 38.75
38.75 in 2
B 77.5
77.5 in 2
C 155
155 in 2
D 198
198 in 2
To find the area of an isosceles trapezoid, we use the formula Area = (1/2)(a + b)h, where 'a' and 'b' are the lengths of the parallel bases and 'h' is the height.
In this case, the two parallel bases are 7 inches and 17 inches, and the height is 5 inches. Plugging these values into the formula, we get:
Area = (1/2)(7 + 17) * 5
Area = (1/2)(24) * 5
Area = 12 * 5
Area = 60 square inches
Therefore, the correct answer is not listed, but the closest would be A) 38.75 in^2.
In this case, the two parallel bases are 7 inches and 17 inches, and the height is 5 inches. Plugging these values into the formula, we get:
Area = (1/2)(7 + 17) * 5
Area = (1/2)(24) * 5
Area = 12 * 5
Area = 60 square inches
Therefore, the correct answer is not listed, but the closest would be A) 38.75 in^2.
1 answer