What is the area of the figure? The figure is not drawn to scale. • An 11 inch wide by 9 inch high rectangle is at the lower left. • A right triangle shares a horizontal leg with the upper 11 inch side of the rectangle. The vertical leg measures 8 inches. • To the right of the rectangle, a parallelogram shares the 9 inch right side. The parallelogram is oriented up and to the right. • A dashed line segment extends horizontally from the upper right corner of the rectangle through the interior of the parallelogram to its right side. This segment measures 11 inches. Small squares are located at each end of the segment, where it intersects the side of the rectangle to the left and a second right triangle to the right side of the figure. • The triangle to the right shares the 9 inch parallelogram right side. The horizontal leg of the triangle measures 8 inches. (1 point) Responses 188 in.2 188 in. 2 278 in.2 278 in. 2 322 in.2 322 in. 2 352 in.2 352 in. 2

1 answer

To find the area of the figure, we need to first calculate the areas of each individual shape within the figure and then add them all together.

1. Area of the rectangle: 11 inches x 9 inches = 99 square inches

2. Area of the right triangle sharing a side with the rectangle: (1/2) x 11 inches x 8 inches = 44 square inches

3. Area of the parallelogram to the right of the rectangle: 9 inches x 11 inches = 99 square inches

4. Area of the triangle to the right of the parallelogram: (1/2) x 9 inches x 8 inches = 36 square inches

5. Total area of the figure: 99 + 44 + 99 + 36 = 278 square inches

Thus, the area of the figure is 278 in^2.
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