if you trust that the vertices do in fact form a rectangle, then just find the lengths of sides wx and wz
wx has length 3√2
wz has length 4√2
the rectangle thus has area 24
What is the area of rectangle wxyz with vertices w(0,1),x(3,4),y(-1,8) z (-4,5) to the nearest unit?
11 answers
thank you
Hello Steve!
To help everyone else who come across this problem and still don't get it like me,
to find the "lengths" you will have to use the Distance Formula.
d = �ã(x2 - x1)^2 +(y2 - y1)^2)
so, just insert the wx values in this and then do it again for the wz values and times the two values together to get your answer. Hoped I helped!! :)
To help everyone else who come across this problem and still don't get it like me,
to find the "lengths" you will have to use the Distance Formula.
d = �ã(x2 - x1)^2 +(y2 - y1)^2)
so, just insert the wx values in this and then do it again for the wz values and times the two values together to get your answer. Hoped I helped!! :)
*d = �ã(x2 - x1)^2 +(y2 - y1)^2)
*the symbol won't show for me, sorry!**
d = (square root)((x2 - x1)^2 +(y2 - y1)^2)
d = (square root)((x2 - x1)^2 +(y2 - y1)^2)
24 square units
24
dose anyone got all the answers im so behind
1 is b.22 in.
2 is b. 20 ft.
3 is d. 24 square units
That's all I have so far
2 is b. 20 ft.
3 is d. 24 square units
That's all I have so far
i got 10 for number 2 weeb
J
11 answers