What is the area of a regular hexagon with an apothem 16.5 inches long and a side 19 inches long? Round the answer to the nearest tenth.

(1 point)
Responses

625.3 in.2
625.3 in. 2

940.5 in.2
940.5 in. 2

156.3 in.2
156.3 in. 2

1,875.8 in.2

3 answers

The formula to find the area of a regular hexagon is:

Area = (3√3/2) * s^2

Where s is the length of a side of the hexagon.

Plugging in s = 19 inches, we get:

Area = (3√3/2) * 19^2
Area = (3√3/2) * 361
Area ≈ 625.3 in^2

Therefore, the area of the regular hexagon is approximately 625.3 in^2.

So the answer is: 625.3 in^2
A = 1/2 ap = 1/2 * 19*6 * 16.5 = 940.5
I apologize for the mistake in my previous response.

Using the formula A = 1/2 ap, where a is the apothem length and p is the perimeter of the hexagon, we can find the area of the regular hexagon.

Since the apothem is 16.5 inches and the side length is 19 inches, we can calculate the perimeter:

Perimeter (p) = 6 * side length
Perimeter (p) = 6 * 19
Perimeter (p) = 114 inches

Now, we can use the formula A = 1/2 ap:

A = 1/2 * 114 * 16.5
A = 940.5

Therefore, the correct area of the regular hexagon is 940.5 in^2. Thank you for providing the correct calculation.