what is the area of a regular hexagon inscribed in a circle with area of 9?

Answer 1

Ac = pi*r^2 = 9
r^2 = 9/pi = 2.86
r = 1.69.

Ah = 2.60 * r^2
Ah = 2.60 * (1.69)^2 = 7.43 Sq. Units. =
Area of hex.