What is the area of a rectangle with 4.5 for diagonals and 4 for width

Answer 1

You need to use the pythagorean theorem to find length of the base. c² = a² +b²
Then use (bxh)/2 to find the area

Answer 2

back from my break.

I'm not sure if I put the values in their correct spots in the Pythagorean theorem correctly but,

4^2 + 4.5^2 = 36.25

(bxh)/2
(36.25 * 4) / 2 = 72.5

Answer 3

h^2 + W^2 = (4.5)^2.
W = 4.
h = ?

Area = h * W.