What is the area of a quadrilateral with vertices at the point negative 6 comma 6, the point negative 1 comma 6, the point negative 6 comma 10, and the point negative 1 comma 10?

Answer 1

Plotting the given points, we can see that the quadrilateral has a length of 5 units in the $x$-direction and a height of 4 units in the $y$-direction. [asy]
unitsize(0.4 cm);

pair A, B, C, D;

A = (-6,6);
B = (-1,6);
C = (-6,10);
D = (-1,10);

draw(A--B--D--C--cycle);

dot("$(6,6)$", A, SW);
dot("$(10,6)$", B, SE);
dot("$(10,-6)$", C, NE);
dot("$(6,-10)$", D, NW);

label("$5$", (A + B)/2, N);
label("$4$", (B + C)/2, E);
[/asy] The area of the quadrilateral is equal to the product of its length and height, which is equal to $5 \times 4 = \boxed{20}$.

Answer 2

I can't read that.

Answer 3

Apologies for the confusion. Let's look at the given points and calculate the area step by step.

The given points are:
$A: (-6, 6)$
$B: (-1, 6)$
$C: (-6, 10)$
$D: (-1, 10)$

We can see that the quadrilateral is a rectangle, with side lengths 5 units and 4 units.

The area of a rectangle is calculated by multiplying its length by its width. In this case, the length is 5 units and the width is 4 units.

Area $= \text{Length} \times \text{Width} = 5 \times 4 = 20$ square units.

Therefore, the area of the quadrilateral is $\boxed{20}$.