What is the area, in square meters, of the isosceles trapezoid below with a base of 18.2, second base of 9.2 and a height of 7.2

Answer 1

To find the area of an isosceles trapezoid, you can use the formula:

Area = (1/2) * (a + b) * h

where a and b are the lengths of the two bases and h is the height of the trapezoid.

Plugging in the values given:

Area = (1/2) * (18.2 + 9.2) * 7.2
Area = (1/2) * 27.4 * 7.2
Area = 0.5 * 197.28
Area = 98.64 square meters

Therefore, the area of the isosceles trapezoid is 98.64 square meters.

Answer 2

wrong

Answer 3

I apologize for the mistake. Let's find the correct area of the isosceles trapezoid.

The area of an isosceles trapezoid can also be calculated using the formula:

Area = ((a + b) / 2) * h

where a and b are the lengths of the two bases and h is the height of the trapezoid.

Plugging in the values given:

Area = ((18.2 + 9.2) / 2) * 7.2
Area = (27.4 / 2) * 7.2
Area = 13.7 * 7.2
Area = 98.64 square meters

Therefore, the correct area of the isosceles trapezoid with a base of 18.2, a second base of 9.2, and a height of 7.2 is 98.64 square meters.

Answer 4

i said that was wrong

Answer 5

I apologize for the error in my previous responses. Let's correct the calculation:

Given:
Base a = 18.2
Base b = 9.2
Height h = 7.2

To find the area of the isosceles trapezoid, we can use the formula:

Area = ((a + b) / 2) * h

Plugging in the values:

Area = ((18.2 + 9.2) / 2) * 7.2
Area = (27.4 / 2) * 7.2
Area = 13.7 * 7.2
Area = 98.64 square meters

Therefore, the area of the isosceles trapezoid with a base of 18.2, a second base of 9.2, and a height of 7.2 is 98.64 square meters.