Asked by tyger2020
What is the angular momentum of the Moon in its orbit around Earth?
I assume I need the mass of the moon, radius of the moon, and angular velocity of the moon. Found those on google, plugged them into my formula (angular momentum = Iw) and got the wrong answer...
I used moment of inertia = (2mr^2)/5
mass = 7.34767309 × 10^22 kg
radius = 1,737,000 meters
angular velocity = 2.43 x 10^-7
Which of these values is wrong?
I assume I need the mass of the moon, radius of the moon, and angular velocity of the moon. Found those on google, plugged them into my formula (angular momentum = Iw) and got the wrong answer...
I used moment of inertia = (2mr^2)/5
mass = 7.34767309 × 10^22 kg
radius = 1,737,000 meters
angular velocity = 2.43 x 10^-7
Which of these values is wrong?
Answers
Answered by
bobpursley
Moment of Inertia for a mass rotating about a point: mr^2
angular momentum=mr^2w=mr^2*2PI/period)
look period up, about 27.3 days, convert to seconds
The orbital angular momentum of the Moon is about 2.9 x 10^34 kgm^2/s
angular momentum=mr^2w=mr^2*2PI/period)
look period up, about 27.3 days, convert to seconds
The orbital angular momentum of the Moon is about 2.9 x 10^34 kgm^2/s
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