What is the angular momentum of a 2.7 kg uniform cylindrical grinding wheel of radius 12 cm when rotating at 1600 rpm? How much torque is required to stop it in 4.4 s?

Answer 1

The angular momenturm is I*w, where
I = (1/2) M R^2
and w is the angular veocity.

The required torque*time to stop rotation is I*w. Therefore
(Torque to stop) = (I*w)/(time)