500 * 1.54 = x
500 * x * 2.50^2
What is the angular momentum (in kilogram-meter^2/second) of a 500.0 g ball rotating on the end of a string in a circle of radius 1.54 m at an angular speed of 2.50 rad/s?
2 answers
thank you,
but since it has to be in kg, do i do the same thing but with
0.5*1.54=0.77
0.5*0.77*2.50^2 = 2.406 kgm^2/s
but since it has to be in kg, do i do the same thing but with
0.5*1.54=0.77
0.5*0.77*2.50^2 = 2.406 kgm^2/s