The AD624AD is a instrumentation amplifier, which means that the output voltage will depend on the gain of the circuit. The gain of the AD624AD is set by an external resistor, and is given by:
Gain = 2 + (49.4 kΩ / Rg)
where Rg is the resistance of the external gain resistor.
Assuming a gain of 100 (corresponding to a gain resistor of 485 Ω), the output voltage of the AD624AD can be calculated as:
Vout = Gain x V1 = 100 x 10 mVpk = 1 Vpk
Note that the output voltage is given in peak (not RMS) values.
Therefore, the amplitude of the output voltage of the AD624AD circuit is 1 Vpk.
What is the amplitude of the output voltage of AD624AD circuit?
V1 = 10mVpk, 1kHz
VCC = 9V
VEE = -9V
3 answers
The options are
a) 200 mV
b) -10 mV
c) -2V
d) 2V
a) 200 mV
b) -10 mV
c) -2V
d) 2V
None of the options match the calculated result of 1 Vpk. Therefore, the answer cannot be determined from the given options.