What is the activity coefficient of H^+ in a solution containing 0.073 M HCl and 0.0090 M Ca(ClO4)2?
What is the pH of the solution?
I believe I have to find the ionic strength of the solution first, but I don't know how to find it when 2 solutions are involved.
3 answers
mu = 1/2[(A)Za^2 + (B)Zb^2 + (C)(Zc^2)....
HCl------H+ + Cl-
0.073 0.073 0.073 M
Ca(ClO4)2 --Ca+2 + 2ClO4-
0.009 0.009 2*0.009 =0.018M
µ= ½{[H+].(+1)2 + [Cl-].(-1)2 + [Ca+2].(+2)2 + [2ClO4-].(-1)2}
µ= ½{[0.073].(+1)2 + [0.073].(-1)2 + [0.009].(+2)2 + [0.018].(-1)2}=0.146+ (0.036+0.52)=.146+0.556=1/2(0.702 )
µ= 0.351 M
0.073 0.073 0.073 M
Ca(ClO4)2 --Ca+2 + 2ClO4-
0.009 0.009 2*0.009 =0.018M
µ= ½{[H+].(+1)2 + [Cl-].(-1)2 + [Ca+2].(+2)2 + [2ClO4-].(-1)2}
µ= ½{[0.073].(+1)2 + [0.073].(-1)2 + [0.009].(+2)2 + [0.018].(-1)2}=0.146+ (0.036+0.52)=.146+0.556=1/2(0.702 )
µ= 0.351 M
dont
1 answer