To find the acceleration vector of the negative charge, we need to use the equation of motion for an object under the influence of an electrostatic force.
The electrostatic force is given by Coulomb's law:
Fe = k * (q1 * q2) / r^2
where Fe is the electrostatic force, k is the Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.
In our example, the negative charge has a charge of 250 me (millielectrons) and is under the influence of an electrostatic force.
Since the gravitational force and force due to air resistance are negligible compared to the electrostatic force, we can ignore them.
Therefore, the equation of motion is:
Fe = m * a
where m is the mass of the negative charge and a is the acceleration.
Substituting Fe with the electrostatic force:
k * (q1 * q2) / r^2 = m * a
Rearranging the equation to solve for acceleration a:
a = (k * q1 * q2) / (m * r^2)
Plugging in the values:
k = 9 x 10^9 Nm^2/C^2 (Coulomb's constant)
q1 = charge of the negative charge = 250 me = 250 * 1.6 x 10^(-19) C (millielectrons converted to Coulombs)
q2 = charge of the positive charge = 250 me = 250 * 1.6 x 10^(-19) C (millielectrons converted to Coulombs)
m = mass of the negative charge = 750 g = 750 * (1/1000) kg (grams converted to kilograms)
r = distance between the charges (not given)
Let's assume that the distance between the charges is 1 meter (r = 1 m) for simplicity.
Now, we can calculate the acceleration vector a:
a = (9 x 10^9 Nm^2/C^2 * (250 * 1.6 x 10^(-19) C) * (250 * 1.6 x 10^(-19) C)) / (750 * (1/1000) kg * (1 m)^2)
Simplifying the equation gives the acceleration vector of the negative charge.
What is the acceleration vector of the negative charge from the example above if its charge is 250 me and its mass is 750 9? The gravitational force and force due to air resistance are negligible compared to the electrostatic force so they can be ignored.
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