What is the 28th term of the sequence an = an−1 + 5.2, if the 26th term is 42.3?

Answer 1

Since $a_{26}=42.3$, we know that $a_{27}=a_{26}+5.2=42.3+5.2=47.5.$ Then $a_{28}=a_{27}+5.2=47.5+5.2=\boxed{52.7}.$