Ask a New Question
Search
what is n to the 101 power and how would you use progression to solve it?
1 answer
N^(k+1) = N * N^k
N
so
N^0 = 1
N^1 = 1*N
N^2 = N * N^1
N^3 = N * N^2
.
.
.
N^101 = N * N^100
Ask a New Question
or
answer this question
.
Similar Questions
The 9th term of an arithmetic progression is 4+5p and the sum of the four terms of the progression is 7p-10, where p is a
1 answer
The first, the third and the seventh terms of an increasing arithmetic progression are three consecutive terms of a geometric
4 answers
The 4th, 6th and 9th term of an arithmetical progression form the first three times of a geometric progression. If the first
5 answers
In an infinite geometric progression with positive terms and with a common ratio |r|<1, the sum of the first three terms is 26/3
1 answer
more similar questions