http://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/implicitdiffdirectory/ImplicitDiff.html
That is an excellent discussion.
Here is an example:
x^3 + xy^2 + x^2 y=14 find dy/dx
by implicit diff:
3x^2 dx/dx + y^2 dx/dx + 2yxdy/dx +2xydx/dx+x^2 dy/dx=0
butdx/dx is one, so
3x^2+y^2+2xy + dy/dx (2xy+x^2)=0
so dy/dx=-(3x^2+y^3 +2xy)/(2xy-x^2)
What is implicit differentiation...as in what would be the steps in solving it. I read my textbook but it seems very confusing.
1) Differentiate both sides with respect to x
2) Realize that y is a function of x
3) Solve for y
Plus the d/dx notation made it even more confusing. Can someone please explain this to me simply? Thanks
1 answer