What is hyperbole?

Responses:

a description that uses extreme exaggeration to make a point about something

a description that makes something seem smaller or less significant than it is

a figure of speech that uses two words with opposite or conflicting meanings to create an effect

a figure of speech that that gives human characteristics or traits to an inanimate object to create imagery

9 answers

Hyperbole is best described as a description that uses extreme exaggeration to make a point about something.

Use the sentence to answer the question.

I crossed the marathon finish line and immediately veered off the trail to collapse, certain I could sleep for days right there in the grass.
What role does hyperbole play in the text?

Responses:

It introduces humor by exaggerating how tired the narrator is.

It stresses the extent of the narrator’s exhaustion in a memorable way.

It creates a sensory experience for readers by presenting a vivid description.

It uses an unrealistic situation to make a point.

The role of hyperbole in the text is best described as It stresses the extent of the narrator’s exhaustion in a memorable way.

Which of the following points is a solution to the linear inequality y>1/9x−2/9

Responses:

(0,−1/9)

(0,−4/9)

(0,−2/9)

(0,−1/3)

To determine which of the given points is a solution to the linear inequality \( y > \frac{1}{9}x - \frac{2}{9} \), we can substitute \( x = 0 \) into the inequality and evaluate the right side.

Substituting \( x = 0 \):

\[ y > \frac{1}{9}(0) - \frac{2}{9} \] \[ y > -\frac{2}{9} \]

Now we check each of the given points to see if the \( y \)-coordinate is greater than \(-\frac{2}{9}\):

  1. (0, -1/9): \(-\frac{1}{9} > -\frac{2}{9}\) (True)

  2. (0, -4/9): \(-\frac{4}{9} > -\frac{2}{9}\) (False)

  3. (0, -2/9): \(-\frac{2}{9} > -\frac{2}{9}\) (False)

  4. (0, -1/3): \(-\frac{1}{3} = -\frac{3}{9}\) and \(-\frac{3}{9} > -\frac{2}{9}\) (False)

The only point that satisfies the inequality is (0, -1/9).

Show which of the following points is part of the solution set for the inequality y≤2/5x+1
Responses:

(−10,6)

(10,5.5)

(10,6)

(10,4)

To determine which of the given points is part of the solution set for the inequality \( y \leq \frac{2}{5}x + 1 \), we can substitute each point into the inequality and check if it satisfies the condition.

  1. Testing point (−10, 6): \[ y \leq \frac{2}{5}(-10) + 1 \] \[ 6 \leq -4 + 1 \] \[ 6 \leq -3 \quad \text{(False)} \]

  2. Testing point (10, 5.5): \[ y \leq \frac{2}{5}(10) + 1 \] \[ 5.5 \leq 4 + 1 \] \[ 5.5 \leq 5 \quad \text{(False)} \]

  3. Testing point (10, 6): \[ y \leq \frac{2}{5}(10) + 1 \] \[ 6 \leq 4 + 1 \] \[ 6 \leq 5 \quad \text{(False)} \]

  4. Testing point (10, 4): \[ y \leq \frac{2}{5}(10) + 1 \] \[ 4 \leq 4 + 1 \] \[ 4 \leq 5 \quad \text{(True)} \]

The only point that satisfies the inequality \( y \leq \frac{2}{5}x + 1 \) is (10, 4).

Kiani is shopping at a bookstore with a budget of $60. Hardbacks cost $12 and paperbacks cost $5. Write a two-variable inequality and determine the constraints of the problem. Which of the following points represents a viable solution?
Responses:

(6,6)

(2,4)

(1,4.5)

(−2,6)

To formulate a two-variable inequality based on Kiani's budget for purchasing hardbacks and paperbacks, let's define:

  • Let \( x \) be the number of hardbacks Kiani buys.
  • Let \( y \) be the number of paperbacks Kiani buys.

Given that hardbacks cost $12 and paperbacks cost $5, the total cost can be modeled by the following inequality:

\[ 12x + 5y \leq 60 \]

Constraints of the Problem:

  1. Non-negativity Constraint: Since Kiani cannot purchase a negative number of books, the following constraints must hold:
    • \( x \geq 0 \) (the number of hardbacks cannot be negative)
    • \( y \geq 0 \) (the number of paperbacks cannot be negative)

With these constraints, we now have the system:

  1. \( 12x + 5y \leq 60 \)
  2. \( x \geq 0 \)
  3. \( y \geq 0 \)

Checking Which Points Are Viable Solutions:

We need to test each of the given points to see if they satisfy the inequality \( 12x + 5y \leq 60 \) as well as the non-negativity constraints.

  1. For (6, 6): \[ 12(6) + 5(6) = 72 + 30 = 102 \quad \text{(not valid since } 102 \nleq 60\text{)} \]

  2. For (2, 4): \[ 12(2) + 5(4) = 24 + 20 = 44 \quad \text{(valid since } 44 \leq 60\text{)} \]

  3. For (1, 4.5): \[ 12(1) + 5(4.5) = 12 + 22.5 = 34.5 \quad \text{(valid since } 34.5 \leq 60\text{)} \]

  4. For (−2, 6): \[ \text{This point cannot be valid because } x \text{ (hardbacks) cannot be negative.} \]

Summary:

From the evaluations above, the points (2, 4) and (1, 4.5) represent viable solutions.

However, if we need to provide a single viable solution in response to the question, (2, 4) is the first viable option found.