What is ∆H0 for this reaction?

Question

Br2(g) → Br2(l)

(∆Hf0 Br2(g) = 30.91 kJ/mol)

1.546 × 101 kJ

–1.546 × 101 kJ

3.091 × 101 kJ

–3.091 × 101 kJ

Answer 1

Br2(g) → Br2(l)
dHorxn = (dHof of products) - (dHof of reactants)
dHo formation Br2(g) = 30.91 kJ/mol
dHo formation Br2(l) = 0 kJ/mol
dHorxn = ?
I obtained the 30.91 from tables I have in a text. You could have looked this up in your text or notes.