To rewrite the expression \( 2(x+1)(x+2) \), we can start by expanding the terms inside the parentheses and then distributing the 2.
-
First, multiply \( (x+1)(x+2) \): \[ (x+1)(x+2) = x^2 + 2x + x + 2 = x^2 + 3x + 2 \]
-
Now, we multiply this result by 2: \[ 2(x^2 + 3x + 2) = 2x^2 + 6x + 4 \]
Thus, the expression \( 2(x+1)(x+2) \) can be rewritten as \( 2x^2 + 6x + 4 \).
The correct answer is: D, 2x^2 + 6x + 4.