Since the vertex is at the origin and the focus is at (-5,0), the parabola opens towards the left.
The distance from the vertex to the focus is given by the equation:
c = 5
The equation of the parabola in standard form is:
(x - h)^2 = 4c(y - k)
where (h,k) is the vertex and c is the distance from the vertex to the focus.
Substituting the values of the vertex and c, we get:
x^2 = 4(5)y
Simplifying, we get:
x^2 = 20y
Therefore, the equation of the parabola with vertex at the origin and focus (-5,0) is x^2 = 20y.
What is an equation of the parabola with vertex at the origin and focus(-5,0)
11 answers
are you sure
I apologize, I made a mistake in the previous answer. The correct equation of the parabola with vertex at the origin and focus (-5,0) is:
(x + 5)^2 = 4py
where p is the distance from the vertex to the directrix. Since the vertex is at the origin, the equation simplifies to:
x^2 = -20y
The negative sign indicates that the parabola opens downwards along the y-axis. Therefore, the equation of the parabola is x^2 = -20y.
(x + 5)^2 = 4py
where p is the distance from the vertex to the directrix. Since the vertex is at the origin, the equation simplifies to:
x^2 = -20y
The negative sign indicates that the parabola opens downwards along the y-axis. Therefore, the equation of the parabola is x^2 = -20y.
is that correct
Yes, that is correct.
do you mean for the y to be squared
Yes, I apologize for my mistake earlier. The correct equation of the parabola with vertex at the origin and focus (-5,0) is:
x^2 = -20y
This equation represents a parabola that opens downwards along the y-axis.
x^2 = -20y
This equation represents a parabola that opens downwards along the y-axis.
so is it x=-1/20y^2
No, the equation x = -(1/20)y^2 does not represent a parabola. The equation of a parabola with a vertical axis of symmetry in the standard form is (x-h)^2 = 4p(y-k), where (h,k) is the vertex and p is the distance between the vertex and the focus (and directrix).
In this case, the vertex is at (0,0) and the focus is at (-5,0), so the distance between the vertex and the focus is 5. Since the parabola opens downwards, the value of p is -5. This gives us the equation:
(x-0)^2 = 4(-5)(y-0)
Simplifying this equation, we get:
x^2 = -20y
Therefore, the equation of the parabola is x^2 = -20y.
In this case, the vertex is at (0,0) and the focus is at (-5,0), so the distance between the vertex and the focus is 5. Since the parabola opens downwards, the value of p is -5. This gives us the equation:
(x-0)^2 = 4(-5)(y-0)
Simplifying this equation, we get:
x^2 = -20y
Therefore, the equation of the parabola is x^2 = -20y.
but its supposed to represent a parabola
I apologize for any confusion. You are correct that x = -(1/20)y^2 represents a parabola, but it is a different parabola than the one with vertex at the origin and focus (-5,0).
The equation x = -(1/20)y^2 represents a horizontal parabola that opens to the left. Its vertex is at the origin, and its focus and directrix are at a distance of 5 (in opposite directions) from the vertex. The equation can be converted into the standard form by using the formula (y-k)^2 = 4p(x-h), which gives:
(y - 0)^2 = 4(-5)(x - 0)
simplifying this gives:
y^2 = -20x
Therefore, the equation of the parabola represented by x = -(1/20)y^2 is y^2 = -20x.
The equation x = -(1/20)y^2 represents a horizontal parabola that opens to the left. Its vertex is at the origin, and its focus and directrix are at a distance of 5 (in opposite directions) from the vertex. The equation can be converted into the standard form by using the formula (y-k)^2 = 4p(x-h), which gives:
(y - 0)^2 = 4(-5)(x - 0)
simplifying this gives:
y^2 = -20x
Therefore, the equation of the parabola represented by x = -(1/20)y^2 is y^2 = -20x.