What is an equation of the line that passes through (−7, 1) and (−3, 9)?

y=2x−15

y=2x+21

y=2x+15

y=2x−21

1 answer

First, find the slope of the line using the formula:

m = (y2 - y1) / (x2 - x1)
m = (9 - 1) / (-3 - (-7))
m = 8 / 4
m = 2

Now that we have the slope, we can use the point-slope formula to find the equation of the line:

y - y1 = m(x - x1)
y - 1 = 2(x - (-7))
y - 1 = 2(x + 7)
y - 1 = 2x + 14
y = 2x + 15

Therefore, the equation of the line that passes through (-7, 1) and (-3, 9) is y = 2x + 15.