The equation of the line that is perpendicular to y + 1 = 1/2 (x - 6) can be found by flipping the slope and changing the sign.
The slope of the given line is 1/2. The slope of the line perpendicular to it is -2.
Now, we have the slope (-2) and the point (-3,4). We can use the point-slope form of the equation of a line to find the equation of the line:
y - y1 = m(x - x1)
y - 4 = -2(x + 3)
y - 4 = -2x - 6
y = -2x - 2
Therefore, the equation of the line that is perpendicular to y + 1 = 1/2 (x - 6) and passes through the point (-3,4) is y = -2x - 2.
What is an equation of the line that is perpendicular to y + 1 = 1/2 (x - 6) and passes through the point (-3,4)?
y + 3 = -2 (x - 4)
y + 3 = 1/2 (x - 4)
y - 4 = -2 (x + 3)
y - 4 = 1/2 (x + 3)
1 answer
1 answer