What is an equation of the line having the given slope and containing the given point

Question

M = -8,(4,6)

Answer 1

Recall the point-slope form of an equation:
y - y1 = m(x - x1)
where
m = slope
(x1, y1) = point on the line
Substituting,
y - 6 = -8(x - 4)
y - 6 = -8x + 32
y = -8x + 38 (slope-intercept form), or
8x + y = 38 (standard form), or
8x + y - 38 = 0 (general form)

Hope this helps~ :3