what is an equation of a parobola with the given vertex and focus?

Question

vertex(5,4) and focus(8,4)
Can someone show me the steps to get the equation please?

Answer 1

the parabola with vertex (0,0) and focus (p,0) is

4px = y^2

We need to shift the vertex to (5,4), so substitute

4p(x-5) = (y-4)^2

The focus is 3 units away from the vertex, so p=3, and we have

12(x-5) = (y-4)^2

Answer 2

So x=1/12(y-4)^2+5 would be the answer?

Answer 3

C
D
C
B
A
100% Parabolas Unit 7 Lesson 2

Answer 4

1.) focus: (0,3) ; directrix: y = -3
2.) x=-1/19^y^2
3.) y=1/8x^2
4.) vertex (3,3); focus (3,6); directrix y= 0
5.) 1/12 (y-4)^2+5

Answer 5

Countess Nightmare and Imposter are 100% correct! Thankssss!

Answer 6

Correct ^