form (opens right)
(y-4)^2 = 4 a (x-5)
a is distance from vertex to focus = 8-5 = 3
so
(y-4)^2 = 12 (x-5) = 12 x - 60
12 x = (y-4)^2 + 60
x = (1/12) (y-4)^2 + 5
like a. but 1/12 not 1/2 Typo?
What is an equation of a parabola with the given vertex and focus?
Vertex: (5, 4)
Focus: (8, 4)
a. x = 1/2 (y - 4)^2 + 5
b. y = 1/2 (x + 4)^2 - 5
c. x = 1/2 (y + 4)^2 - 5
d. y = 1/2 (x - 4)^2 + 5
1 answer
1 answer