First, find the slope:
m = (y2 - y1) / (x2 - x1)
m = (1 - (-3)) / (3 - 1)
m = 4 / 2
m = 2
Now, plug the slope and one of the points into the slope-intercept form equation (y = mx + b) to solve for the y-intercept (b):
1 = 2(3) + b
1 = 6 + b
b = 1 - 6
b = -5
Therefore, the equation of the line passing through the points (1, –3) and (3, 1) in slope-intercept form is:
y = 2x - 5
What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)
1 answer