This is really a funny kind of question in that you want to add HNO3 to make a final concn of 0.1M. I am assuming this must be a Ka problem that works like this.
Al(H2O)6 + H2O --> [Al(H2O)5(OH)]^2+ + [H3O]^+
Look up the value of Ka for Al(H2O)6. It may not be all that easy to find but Google should help. I have it in one of my texts.
Write the Ka expression for that reaction.
Substitute 0.15 for Al(H2O)6 and 0.1 for [H3O]^+ and solve for the concentration of [Al(H2O)5(OH)]^2+
What is [Al(H2 O)5(OH)2+] in a 0.15-M solution of Al(NO3)3 that contains enough of the strong acid HNO3 to bring [H3O+] to 0.10 M?
1 answer
1 answer