What is a simplified form of the expression [sec^2x-1]/[(sinx)(secx)]?

Question

a. cot x
b. csc x
c. tan x*****
d. sec x tan x

I think this is the correct answer, but I do not understand why. Can someone please explain?

Answer 1

sec^2x-1=tan^2x
So, using that, you have

sin^2x/cos^2x * 1/sinx * cosx = sinx/cosx = tanx

Answer 2

Thank you Steve!