Any function? The simplest way to do this would be to assume a cubic function with roots -1, -5, and 3. This would mean it would be factorable into:
(x+1)(x+5)(x-3). Simply multiply these three functions together and there's an answer.
What is a polynomial function in standard form with zeros 1, 2, 3, and –3?
7 answers
y = (x-1)(x-2)(x-3)(x+3)
= (x-1)(x-2)(x^2 - 9)
=(x^2 -3x+2)(x^2-9)
= x^4 - 3x^3 - 7x^2 + 27x - 18
= (x-1)(x-2)(x^2 - 9)
=(x^2 -3x+2)(x^2-9)
= x^4 - 3x^3 - 7x^2 + 27x - 18
-1,2,5
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smh
I'm sorry, is there something I can assist you with?