no, because 23 is not divisible by 3!
You want B, because 27 is divisible by 3, but not divisible by 6.
What is a counterexample of the following conjecture?
Conjecture: Any number that is divisible by 3 is also divisible by 6
36
27
23
18
Is it C, 23? A little confused:p Please help? Thanks
2 answers
Ah, ok, thanks Steve. I got confused to what exactly counterexample meant in this.
1 answer