what is 8- 7 1/4

Answer 1

To solve $8-7\frac{1}{4}$, first convert $7\frac{1}{4}$ into an improper fraction.

1. Convert $7\frac{1}{4}$: $$7\frac{1}{4}=7+\frac{1}{4}=\frac{7\times 4}{4}+\frac{1}{4}=\frac{28}{4}+\frac{1}{4}=\frac{29}{4}$$

2. Now subtract $8$ from $\frac{29}{4}$. First, convert $8$ into a fraction with a denominator of $4$: $$8=\frac{8\times 4}{4}=\frac{32}{4}$$

3. Now perform the subtraction: $$\frac{32}{4}-\frac{29}{4}=\frac{32-29}{4}=\frac{3}{4}$$

So, $8-7\frac{1}{4}=\frac{3}{4}$.

Answer 2

-4 5/11 - 2 4/11

Answer 3

To solve $-4\frac{5}{11}-2\frac{4}{11}$, we first convert both mixed numbers into improper fractions.

1. Convert $-4\frac{5}{11}$: $$-4\frac{5}{11}=-(4\times 11+5)=-(44+5)=-\frac{49}{11}$$

2. Convert $-2\frac{4}{11}$: $$-2\frac{4}{11}=-(2\times 11+4)=-(22+4)=-\frac{26}{11}$$

Now, we can subtract the two improper fractions: $$-\frac{49}{11}-\frac{26}{11}=-\left(\frac{49+26}{11}\right)=-\frac{75}{11}$$

Next, we can convert $-\frac{75}{11}$ back into a mixed number:

• Divide $75$ by $11$:
  • $75÷11=6$ (whole number part) remainder $9$.

So, $$-\frac{75}{11}=-6\frac{9}{11}$$

Thus, the final answer is: $$-4\frac{5}{11}-2\frac{4}{11}=-6\frac{9}{11}$$