What is 72x^2+44x+48/4x^2

Answer 1

To simplify the expression \(\frac{72x^2 + 44x + 48}{4x^2}\), we can divide each term in the numerator by \(4x^2\):

1. Divide each term by \(4x^2\): \[ \frac{72x^2}{4x^2} + \frac{44x}{4x^2} + \frac{48}{4x^2} \]

2. Calculate each term:

   • \(\frac{72x^2}{4x^2} = 18\)
   • \(\frac{44x}{4x^2} = \frac{44}{4x} = \frac{11}{x}\)
   • \(\frac{48}{4x^2} = \frac{12}{x^2}\)

3. Combine the results: \[ 18 + \frac{11}{x} + \frac{12}{x^2} \]

Therefore, the simplified expression is: \[ 18 + \frac{11}{x} + \frac{12}{x^2} \]