Asked by DrBob222

What I wrote is the balanced ionic equation. The ++ are written as exponents and could be written as we usually do it as
Cu^+2 + Zn ==> Zn^+2 + Cu. For the molecular equation, it is
Cu(NO3)2 + Zn ==> Zn(NO3)2 + Cu


So the ionic equation for adding copper(II)nitrate to pure zinc is:
Cu^2N+Zn---> Zn^2+Cu

then would the balanced equation be:
Cu^2N+Zn---> Zn^2CuN

No. Didn't I write the balanced equation for you yesterday. What is with the ^2N? I know the caret means exponent but what is N?

Cu<sup>++</sup> + Zn ==>Zn<sup>++</sup> + Cu

I thought I was supposed to add nitrogen to both sides of the equation to balanec it. So is Cu++Zn--->Zn++Cu
the balanced equation for copper(II)nitrate plus pure zinc?

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