What horizontal force is needed to push a hospital bed of mass 120 kg at a constant speed up a smooth sloping plane inclined at an angle of 37 degrees above the ground?

Answer 1

m*g = 120kg * 9.8N/kg = 1176 N. = Wt. of
the bed.

Fp = 1176*sin37 = 707.73 N. = Force
parallel to the incline.

Fn = 1176*cos37 = 939.20 N. = Normal =
Force perpendicular to the incline.

Fap-Fp = m*a
Fap-707.73 = m*0 = 0
Fap = 707.73 N. = Force applied parallel
to the incline.

Fx = Fap*cos A = 707.73*cos37 = 565 N.
= Hor. force applied.