2NaOH + CO2 ==> Na2CO3 + H2O
2OH^-(aq) + CO2(g) ==> CO3^2-(aq) + H2O(l)
What happens when you dissolve CO2 (g) into NaOH (aq). (explain using net ionic equation)
2 answers
This is a 2-step process...
1. Carbon dioxide and water react to make carbonic acid.
CO2(aq)+H2O(l)⟶H2CO3(aq)
Carbonic acid reacts with hydroxide ions (acid/base metathesis rxn) to make sodium bicarbonate and water.
2. H2CO3(aq)+NaOH(aq)⟶NaHCO3(aq)+H2O(l)
Ionic Equation => H2CO3(aq) + Na^+(aq) + OH^-(aq) ==> Na^+(aq) + HCO3^-(aq) + H2O(l)
Net Ionic Equation (Na^+(aq) is spectator ion):
H2CO3(aq) + OH^-(aq) ==> HCO3^-(aq) + H2O(l)
1. Carbon dioxide and water react to make carbonic acid.
CO2(aq)+H2O(l)⟶H2CO3(aq)
Carbonic acid reacts with hydroxide ions (acid/base metathesis rxn) to make sodium bicarbonate and water.
2. H2CO3(aq)+NaOH(aq)⟶NaHCO3(aq)+H2O(l)
Ionic Equation => H2CO3(aq) + Na^+(aq) + OH^-(aq) ==> Na^+(aq) + HCO3^-(aq) + H2O(l)
Net Ionic Equation (Na^+(aq) is spectator ion):
H2CO3(aq) + OH^-(aq) ==> HCO3^-(aq) + H2O(l)